METR 2413 - Homework 7 Name:
_____________________________
Date
assigned:
Date due:
1. Using the equation for potential temperature with κ = R/cp
derive the following expression
for the vertical gradient of potential temperature:
.

Take ln [ ] è ln(θ) = ln(T) + κln(1000) – κln(p) (now take d/dz)
(1/θ)dθ/dz = (1/T)dT/dz + 0 – (κ/p)dp/dz
(use hydrostatic approx: dp/dz = -ρg, ideal gas law: p = ρRT
and κ = R/cp)
(1/θ)dθ/dz = (1/T)dT/dz – [(R/cp)/(ρRT)](-ρg) (now simplify the final term)
(1/θ)dθ/dz = (1/T)dT/dz + (1/T)(g/cp)
(multiply by θ and note that
g/cp is the dry adiabatic lapse rate: Γd)
dθ/dz = (θ/T)dT/dz + (θ/T)Γd
or:
(4 points)
What does this equation imply about the change of potential temperature with height for dry adiabatic conditions?
If dry
adiabatic then dT/dz = - Γd è From the equation
this gives dθ/dz = 0
Or, the
potential temperature (θ) is constant with height for dry adiabatic
conditions. (1 point)
What is the sign of the vertical gradient of potential temperature for unstable dry adiabatic motion?
For unstable dry adiabatic motion we
must have dT/dz < -Γd
From
, dθ/dz must therefore be negative,
since the
term will be less
than zero for this
case. (1 point)
2. If the morning environmental temperature at 850 hPa is 10oC, estimate the afternoon maximum temperature at sea level assuming a mixed layer depth of 150 hPa. Under what environmental conditions is this estimate most valid? Would you expect the maximum temperature to be higher or lower if the mixed layer depth was shallower than 150 hPa?
The maximum temperature will be equal to
θ(850mb), assuming that the boundary layer
completely mixes out and becomes dry adiabatic.

Use Max Temperature =
θ(850mb) = (283K)(1000mb/850mb)(287/1004)
Max Temperature ~ 296.5K = 23.5°C (2
points)
This
estimate will be most valid with clear skies and moderate/strong
winds. These conditions will provide
the greatest amount of mixing, resulting in a dry adiabatic layer. (1 point)
If the
mixed layer depth was shallower, a lower maximum temperature would be
expected. (1 point)